Why the circuit Current (I) decrease, when Inductance (L) or inductive reactance (XL) increases in inductive circuit?

Explain the statement that " In Inductive circuit, when Inductance (L) or inductive reactance (X_L) increases, the circuit Current (I) decrease" 
OR
Why the circuit Current (I) decrease, when  Inductance (L) or inductive reactance (X_L) increases in inductive circuit?

Explanation:
We know that, I = V / R, 
but in inductive circuit, I = V/X_{L
So Current in inversely proportional  to the Current ( in inductive circuit.
Let's check with an example..}  
Suppose, when Inductance (L) = 0.02H 

V=220, R= 10 Ω, L=0.02 H, f=50Hz.

X_L = 2πfL = 2 x 3.1415 x 50 x 0.02 = 6.28 Ω 

Z = √ (R²+X_L²) = √ (10² + 6.28²) = 11.8 Ω

I = V/Z = 220/11.8 = 18.64 A

Now we increases Inductance (L) form 0.02 H to 0.04 H,

V=220, R= 10 Ω, L=0.04 H, f=50Hz.

X_L = 2πfL= 2 x 3.1415 x 50 x 0.04 = 12.56 Ω

Z = √ (R²+X_L²) = √ (10² + 12.56²) = 16.05 Ω

I = V/Z = 220 / 16.05 = 13.70 A

Conclusion:

We can see that, When inductance (L) was 0.02, then circuit current were 18.64 A,

But, when Circuit inductance increased from 0.02H to 0.04 H, then current decreased from13.70 A to 18.64A.

Hence proved,

In inductive circuit, when inductive reactance X_L increases, the circuit current decreases, and Vice Virsa.