Why is the starting current high in a DC motor?

In DC motors, Voltage equation is V=Eb-IaRa (V = Terminal voltage,Eb= Back emf in Motor,Ia = Armature current,Ra = Armature resistance).At starting,Eb is zero. Therefore, V=IaRa, Ia = V/Ra , where Ra is very less like 0.01ohm.i.e,Ia will become enormously increased